7) Submarines need to be extremely strong to withstand the extremely high pressure of water pushing down on them. An experimental research submarine with a volume of 15,000 liters has an internal pressure of 1.2 atm. If the pressure of the ocean breaks the submarine forming a bubble with a pressure of 250 atm pushing on it, how big will that bubble be? P1v1=p2v2 V2=p1v1/p2=v2=(1.2)15000/250 ans.72 L harlene p. hatalan
7) Submarines need to be extremely strong to withstand the extremely high pressure of water pushing down on them. An experimental research submarine with a volume of 15,000 liters has an internal pressure of 1.2 atm. If the pressure of the ocean breaks the submarine forming a bubble with a pressure of 250 atm pushing on it, how big will that bubble be? P1v1=p2v2 V2=p1v1/p2=v2=(1.2)15000/250 ans.72 L harlene p. hatalan
Priscilla S. Akut Boyles law 8.) Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver? V1=0.05L V2=? P1=250 atm P2=50.0 atm
2) A man heats a balloon in the oven. If the balloon initially has a volume of 0.4 liters and a temperature of 20 0C, what will the volume of the balloon be after he heats it to a temperature of 250 0C? V2=v1t2/t1=v2=(0.4)523.15/293.15 Ans.0.71 L Harlene p. hatalan
8) Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver? P1v1=p2v2 V2=p1v1/p2=v2=(0.05)250/50.0=v=0.25L,yes Racma Mauna 3-john
Priscilla S.Akut Charles law 3.)On hot days, you may have noticed that potato chip bags seem to “inflate”, even though they have not been opened. If I have a 250 mL bag at a temperature of 19 0C, and I leave it in my car which has a temperature of 600 C, what will the new volume of the bag be?
V1=250 mL V2=? T1=19+273.15=292.15 T2=60+273.15=333.15
V2=V1T2 ---- T1 V2=333.15/292.15(250 mL) V2=(1.14)(250 mL) V2=285 mL
4) The highest pressure ever produced in a laboratory setting was about 2.0 x 106 atm. If we have a 1.0 x 10-5 liter sample of a gas at that pressure, then release the pressure until it is equal to 0.275 atm, what would the new volume of that gas be? 72.7 L
Priscilla S.Akut Combined gas law 1.)If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?
2) A gas takes up a volume of 17 liters, has a pressure of 2.3 atm, and a temperature of 299 K. If I raise the temperature to 350 K and lower the pressure to 1.5 atm, what is the new volume of the gas? P1v1/t1=p2v2/t2 V2=p1v1t2/t1p2 =(2.3)(17 L)(350 K)/(1.5)(299 K) Ans.30.5 Harlene P. hatalan
Hazel Paclar 1.)Combined gas law 1.)If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?
Flower Mae S. Nugas combined gas law p1=12atm,,v1=23L,,T1200k,,P2=14atm,,T2=300k,,V2?,, V2=P1V1T2/P2T1 V2=(12atm/14atm)(300k/200k)(23L V2=(0.86)(1.5)(23L) V2=(1.29)(23L) V2=29.67/29.6
florisa yancha charle"s law 1) The temperature inside my refrigerator is about 40 Celsius. If I place a balloon in my fridge that initially has a temperature of 220 C and a volume of 0.5 liters, what will be the volume of the balloon when it is fully cooled by my refrigerator? P1=o.5 atm P2=? atm 4degree Celsius+22 degree Celsius=26 =26
Combined Gas Law Problems mark jeffrey magparoc 3-john
1) If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas? 29.6 L P1=12 atm P2=14 atm V1=23 L V2=???? T1=200 K T2=300K
florisa yancha dalton"s law A metal tank contains three gases: oxygen, helium, and nitrogen. If the partial pressures of the three gases in the tank are 35 atm of O2, 5 atm of N2, and 25 atm of He, what is the total pressure inside of the tank? 65 atm P1=35 atm,5 atm P2=25 atm =65 atm
Flower Mae S. Nugas charles law no. 2 V1=0.4L,,T1=20 degrees C+273.15=293.15K,,V2=?,,T2=250 degreesC+273.15=523.15K,,V2=V1T1 T1 V2=523.15K 293.15K 0.4L V2=1.7845 V2=0.71L
Charles law 3.)On hot days, you may have noticed that potato chip bags seem to “inflate”, even though they have not been opened. If I have a 250 mL bag at a temperature of 19 0C, and I leave it in my car which has a temperature of 600 C, what will the new volume of the bag be?
V1=250 mL V2=? T1=19+273.15=292.15 T2=60+273.15=333.15
V2=V1T2 ---- T1 V2=333.15/292.15(250 mL) V2=(1.14)(250 mL) V2=285 mL
florisa yancha 3-john the ideal and combined gas laws 3) My car has an internal volume of 2600 liters. If the sun heats my car from a temperature of 200 C to a temperature of 550 C, what will the pressure inside my car be? Assume the pressure was initially 760 mm Hg.
1) The temperature inside my refrigerator is about 40 Celsius. If I place a balloon in my fridge that initially has a temperature of 220 C and a volume of 0.5 liters, what will be the volume of the balloon when it is fully cooled by my refrigerator? 0.47 L V1=0.5 L T2=22’c + 273.15 k=295.15 V2=?? T1=4’c + 273.15k=277.15
4) The highest pressure ever produced in a laboratory setting was about 2.0 x 106 atm. If we have a 1.0 x 10-5 liter sample of a gas at that pressure, then release the pressure until it is equal to 0.275 atm, what would the new volume of that gas be? 72.7 L
5) Some students believe that teachers are full of hot air. If I inhale 2.2 liters of gas at a temperature of 180 C and it heats to a temperature of 380 C in my lungs, what is the new volume of the gas? CHARLES LAW Racma G. Mauna 3 JOHN V1=2.2L V2=? T1=18+273.15=291.15 T2=38+273.15=311.15 V2=v1t2/t1
Charles law 3.)On hot days, you may have noticed that potato chip bags seem to “inflate”, even though they have not been opened. If I have a 250 mL bag at a temperature of 19 0C, and I leave it in my car which has a temperature of 600 C, what will the new volume of the bag be?
V1=250 mL V2=? T1=19+273.15=292.15 T2=60+273.15=333.15
V2=V1T2 ---- T1 V2=333.15/292.15(250 mL) V2=(1.14)(250 mL) V2=285 mL
Boyles law 8.) Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver? V1=0.05L V2=? P1=250 atm P2=50.0 atm
1.)Combined gas law 1.)If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?
P1=12atm P2=14atm V1=23L V2=? T1=200K T2=300K
P1V1T2 V2=------ P2T1 V2=(12atm/14atm)(300K/200k)(23L) V2=(0.86)(1.5)(23L) V2=(1.29)(23L) V2=29.6L ana marie g.hinampas
A(n) __________________ is used to lower the energy required to make a reaction take place. It makes chemical reactions go faster without being consumed.
The thing we measure when we want to determine the average kinetic energy of random motion in the particles of a substance is _temperature_________________.
10) If I have an unknown quantity of gas held at a temperature of 1195 K in a container with a volume of 25 liters and a pressure of 560 atm, how many moles of gas do I have?
The thing we measure when we want to determine the average kinetic energy of random motion in the particles of a substance is_________________. *answer:temperature
The thing we measure when we want to determine the average kinetic energy of random motion in the particles of a substance is_________________. *answer:temperature
Part of the reason that conventional explosives cause so much damage is that their detonation produces a strong shock wave that can knock things down. While using explosives to knock down a building, the shock wave can be so strong that 12 liters of gas will reach a pressure of 3.8 x 104 mm Hg. When the shock wave passes and the gas returns to a pressure of 760 mm Hg, what will the volume of that gas be? *answer:600L
he temperature inside my refrigerator is about 40 Celsius. If I place a balloon in my fridge that initially has a temperature of 220 C and a volume of 0.5 liters, what will be the volume of the balloon when it is fully cooled by my refrigerator? *answer:0.47L
A man heats a balloon in the oven. If the balloon initially has a volume of 0.4 liters and a temperature of 20 0C, what will the volume of the balloon be after he heats it to a temperature of 250 0C? *answer:0.71L submitted by CHERIE MAE GALARPE
Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver? answer:v=0.25L,yes submitted by CHERIE MAE GALARPE
1) 1.00 L of a gas at standard temperature and pressure is compressed to 473 mL. What is the new pressure of the gas? Given: V1 =1.00L P1=1atm V2=473mL P2=?
Volume is inversely proportion to pressure. A decrease in volume means an increase in pressure. Hence, we multiply P1 by a factor of volume that will increase its value. FORMULA: P1V1=P1V2 SOLUTION: P2=(1atm)(1000ml) 473mL P2=2.11atm Kimjay B.Dulalas
1) The temperature inside my refrigerator is about 40 Celsius. If I place a balloon in my fridge that initially has a temperature of 220 C and a volume of 0.5 liters, what will be the volume of the balloon when it is fully cooled by my refrigerator?
Given: V1= 0.5L T1 =40 C + 273 K V2= ? T2= 220 C + 273 K
Use the combined gas law to solve the following problems:
1) If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?
Given: V1 = 23 L P1 = 12 atm T1 = 200 K V2 = ? P2 = 14 atm T2 = 300 K
gezelle marie japona charle's law 2) A man heats a balloon in the oven. If the balloon initially has a volume of 0.4 liters and a temperature of 20 0C, what will the volume of the balloon be after he heats it to a temperature of 250 0C? PROBLEM NO. 2
v1 = 0.4 L T1 = 20 degrees C + 273.15 = 293.15 K V2 = ? T2 = 250 degrees C + 273.15 = 523.15 K
gezelle marie japona combined gas law problem 1) If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?
gezelle marie japona dalton's law A metal tank contains three gases: oxygen, helium, and nitrogen. If the partial pressures of the three gases in the tank are 35 atm of O2, 5 atm of N2, and 25 atm of He, what is the total pressure inside of the tank? 65 atm P1=35 atm,5 atm P2=25 atm =65 atm
gezelle marie8.) Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver? V1=0.05L V2=? P1=250 atm P2=50.0 atm
charles law 1) The temperature inside my refrigeratoris about 4 degrees Celcius.if i place a ballonin my fridge initially has a temp. of 22 degrees celcius and a volume of 0.5 liters.what will be the volume of the balloon when its fully cooled in my refrigerator?
Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver?
1) If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?
Given: V1 = 23 L P1 = 12 atm T1 = 200 K V2 = ? P2 = 14 atm T2 = 300 K
1) 1.00 L of a gas at standard temperature and pressure is compressed to 473 mL. What is the new pressure of the gas? Given: V1 =1.00L P1=1atm V2=473mL P2=?
Volume is inversely proportion to pressure. A decrease in volume means an increase in pressure. Hence, we multiply P1 by a factor of volume that will increase its value. FORMULA: P1V1=P1V2 SOLUTION: P2=(1atm)(1000ml) 473mL P2=2.11atm
Charles law 3.)On hot days, you may have noticed that potato chip bags seem to “inflate”, even though they have not been opened. If I have a 250 mL bag at a temperature of 19 0C, and I leave it in my car which has a temperature of 600 C, what will the new volume of the bag be?
V1=250 mL V2=? T1=19+273.15=292.15 T2=60+273.15=333.15
V2=V1T2 ---- T1 V2=333.15/292.15(250 mL) V2=(1.14)(250 mL) V2=285 mL
4) The highest pressure ever produced in a laboratory setting was about 2.0 x 106 atm. If we have a 1.0 x 10-5 liter sample of a gas at that pressure, then release the pressure until it is equal to 0.275 atm, what would the new volume of that gas be? 72.7 L
rachelle bahancharle's law 2) A man heats a balloon in the oven. If the balloon initially has a volume of 0.4 liters and a temperature of 20 0C, what will the volume of the balloon be after he heats it to a temperature of 250 0C? PROBLEM NO. 2
v1 = 0.4 L T1 = 20 degrees C + 273.15 = 293.15 K V2 = ? T2 = 250 degrees C + 273.15 = 523.15 K
8.) Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver? V1=0.05L V2=? P1=250 atm P2=50.0 atm
dalton's law A metal tank contains three gases: oxygen, helium, and nitrogen. If the partial pressures of the three gases in the tank are 35 atm of O2, 5 atm of N2, and 25 atm of He, what is the total pressure inside of the tank? 65 atm P1=35 atm,5 atm P2=25 atm =65 atm
combined gas law problem 1) If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?
jonalyn hernaiz Boyles law 8.) Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver? V1=0.05L V2=? P1=250 atm P2=50.0 atm
1.)If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?
boyles law 8.) Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver? V1=0.05L V2=? P1=250 atm P2=50.0 atm
jesivel jadap combined gas law problem 1) If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?
jesivel jadap III-JUDE 3.)On hot days, you may have noticed that potato chip bags seem to “inflate”, even though they have not been opened. If I have a 250 mL bag at a temperature of 19 0C, and I leave it in my car which has a temperature of 600 C, what will the new volume of the bag be?
V1=250 mL V2=? T1=19+273.15=292.15 T2=60+273.15=333.15
V2=V1T2 ---- T1 V2=333.15/292.15(250 mL) V2=(1.14)(250 mL) V2=285 mL
Combined gas law 1.)If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?
7) Submarines need to be extremely strong to withstand the extremely high pressure of water pushing down on them. An experimental research submarine with a volume of 15,000 liters has an internal pressure of 1.2 atm. If the pressure of the ocean breaks the submarine forming a bubble with a pressure of 250 atm pushing on it, how big will that bubble be? P1v1=p2v2 V2=p1v1/p2=v2=(1.2)15000/250 ans.72 L LORRAINE G.CALAM
ma.) Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver? V1=0.05L V2=? P1=250 atm P2=50.0 atm
angel rose marie ybanez combined gas law problem 1) If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?
Boyles law 8.) Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver? V1=0.05L V2=? P1=250 atm P2=50.0 atm
Boyles law 8.) Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver? V1=0.05L V2=? P1=250 atm P2=50.0 atm
8) Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver? P1v1=p2v2 V2=p1v1/p2=v2=(0.05)250/50.0=v=0.25L,yes KaReN GANINAY III-JUDE....
Combined gas law 1.)If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?
P1=12atm P2=14atm V1=23L V2=? T1=200K T2=300K
P1V1T2 V2=------ P2T1 V2=(12atm/14atm)(300K/200k)(23L) V2=(0.86)(1.5)(23L) V2=(1.29)(23L) V2=29.6L ana marie g.hinampas
klyndon Boyles law 8.) Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver? V1=0.05L V2=? P1=250 atm P2=50.0 atm
Charles law 3.)On hot days, you may have noticed that potato chip bags seem to “inflate”, even though they have not been opened. If I have a 250 mL bag at a temperature of 19 0C, and I leave it in my car which has a temperature of 600 C, what will the new volume of the bag be?
V1=250 mL V2=? T1=19+273.15=292.15 T2=60+273.15=333.15
V2=V1T2 ---- T1 V2=333.15/292.15(250 mL) V2=(1.14)(250 mL) V2=285 mL
Combined gas law 1.)If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?
P1=12atm P2=14atm V1=23L V2=? T1=200K T2=300K
P1V1T2 V2=------ P2T1 V2=(12atm/14atm)(300K/200k)(23L) V2=(0.86)(1.5)(23L) V2=(1.29)(23L) V2=29.6L ana marie g.hinampas
analeth cartajena III-JUDE.)On hot days, you may have noticed that potato chip bags seem to “inflate”, even though they have not been opened. If I have a 250 mL bag at a temperature of 19 0C, and I leave it in my car which has a temperature of 600 C, what will the new volume of the bag be?
V1=250 mL V2=? T1=19+273.15=292.15 T2=60+273.15=333.15
V2=V1T2 ---- T1 V2=333.15/292.15(250 mL) V2=(1.14)(250 mL) V2=285 mL
jesivel jadap IBoyles law 8.) Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver? V1=0.05L V2=? P1=250 atm P2=50.0 atm
7) Submarines need to be extremely strong to withstand the extremely high pressure of water pushing down on them. An experimental research submarine with a volume of 15,000 liters has an internal pressure of 1.2 atm. If the pressure of the ocean breaks the submarine forming a bubble with a pressure of 250 atm pushing on it, how big will that bubble be? P1v1=p2v2 V2=p1v1/p2=v2=(1.2)15000/250 ans.72 L harlene p. hatalan
1) The temperature inside my refrigerator is about 40 Celsius. If I place a balloon in my fridge that initially has a temperature of 220 C and a volume of 0.5 liters, what will be the volume of the balloon when it is fully cooled by my refrigerator?
Given: V1= 0.5L T1 =40 C + 273 K V2= ? T2= 220 C + 273 K
1) The temperature inside my refrigerator is about 40 Celsius. If I place a balloon in my fridge that initially has a temperature of 220 C and a volume of 0.5 liters, what will be the volume of the balloon when it is fully cooled by my refrigerator?
Given: V1= 0.5L T1 =40 C + 273 K V2= ? T2= 220 C + 273 K
2) A man heats a balloon in the oven. If the balloon initially has a volume of 0.4 liters and a temperature of 20 0C, what will the volume of the balloon be after he heats it to a temperature of 250 0C? V2=v1t2/t1=v2=(0.4)523.15/293.15 Ans.0.71 L
Charles law 3.)On hot days, you may have noticed that potato chip bags seem to “inflate”, even though they have not been opened. If I have a 250 mL bag at a temperature of 19 0C, and I leave it in my car which has a temperature of 600 C, what will the new volume of the bag be?
V1=250 mL V2=? T1=19+273.15=292.15 T2=60+273.15=333.15
V2=V1T2 ---- T1 V2=333.15/292.15(250 mL) V2=(1.14)(250 mL) V2=285 mL
Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver?
Combined gas law 1.)If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?
1.00 L of a gas at standard temperature and pressure is compressed to 473 mL. What is the new pressure of the gas? Given: V1 =1.00L P1=1atm V2=473mL P2=?
Volume is inversely proportion to pressure. A decrease in volume means an increase in pressure. Hence, we multiply P1 by a factor of volume that will increase its value. FORMULA: P1V1=P1V2 SOLUTION: P2=(1atm)(1000ml) 473mL P2=2.11atm
Submarines need to be extremely strong to withstand the extremely high pressure of water pushing down on them. An experimental research submarine with a volume of 15,000 liters has an internal pressure of 1.2 atm. If the pressure of the ocean breaks the submarine forming a bubble with a pressure of 250 atm pushing on it, how big will that bubble be? P1v1=p2v2 V2=p1v1/p2=v2=(1.2)15000/250 ans.72 L
Charles law 3.)On hot days, you may have noticed that potato chip bags seem to “inflate”, even though they have not been opened. If I have a 250 mL bag at a temperature of 19 0C, and I leave it in my car which has a temperature of 600 C, what will the new volume of the bag be?
V1=250 mL V2=? T1=19+273.15=292.15 T2=60+273.15=333.15
V2=V1T2 ---- T1 V2=333.15/292.15(250 mL) V2=(1.14)(250 mL) V2=285 mL
Charles law 3.)On hot days, you may have noticed that potato chip bags seem to “inflate”, even though they have not been opened. If I have a 250 mL bag at a temperature of 19 0C, and I leave it in my car which has a temperature of 600 C, what will the new volume of the bag be?
V1=250 mL V2=? T1=19+273.15=292.15 T2=60+273.15=333.15
V2=V1T2 ---- T1 V2=333.15/292.15(250 mL) V2=(1.14)(250 mL) V2=285 mL
8.) Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver? V1=0.05L V2=? P1=250 atm P2=50.0 atm
8.) Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver? V1=0.05L V2=? P1=250 atm P2=50.0 atm
7) Submarines need to be extremely strong to withstand the extremely high pressure of water pushing down on them. An experimental research submarine with a volume of 15,000 liters has an internal pressure of 1.2 atm. If the pressure of the ocean breaks the submarine forming a bubble with a pressure of 250 atm pushing on it, how big will that bubble be? P1v1=p2v2 V2=p1v1/p2=v2=(1.2)15000/250 ans.72 L
Charles law 3.)On hot days, you may have noticed that potato chip bags seem to “inflate”, even though they have not been opened. If I have a 250 mL bag at a temperature of 19 0C, and I leave it in my car which has a temperature of 600 C, what will the new volume of the bag be?
V1=250 mL V2=? T1=19+273.15=292.15 T2=60+273.15=333.15
V2=V1T2 ---- T1 V2=333.15/292.15(250 mL) V2=(1.14)(250 mL) V2=285 mL
Submarines need to be extremely strong to withstand the extremely high pressure of water pushing down on them. An experimental research submarine with a volume of 15,000 liters has an internal pressure of 1.2 atm. If the pressure of the ocean breaks the submarine forming a bubble with a pressure of 250 atm pushing on it, how big will that bubble be? P1v1=p2v2 V2=p1v1/p2=v2=(1.2)15000/250 ans.72 L
2) A man heats a balloon in the oven. If the balloon initially has a volume of 0.4 liters and a temperature of 20 0C, what will the volume of the balloon be after he heats it to a temperature of 250 0C? V2=v1t2/t1=v2=(0.4)523.15/293.15 Ans.0.71 L
4) The highest pressure ever produced in a laboratory setting was about 2.0 x 106 atm. If we have a 1.0 x 10-5 liter sample of a gas at that pressure, then release the pressure until it is equal to 0.275 atm, what would the new volume of that gas be? 72.7 L
dalton"s law A metal tank contains three gases: oxygen, helium, and nitrogen. If the partial pressures of the three gases in the tank are 35 atm of O2, 5 atm of N2, and 25 atm of He, what is the total pressure inside of the tank? 65 atm P1=35 atm,5 atm P2=25 atm =65 atm
5) Some students believe that teachers are full of hot air. If I inhale 2.2 liters of gas at a temperature of 180 C and it heats to a temperature of 380 C in my lungs, what is the new volume of the gas? CHARLES LAW Racma G. Mauna 3 JOHN V1=2.2L V2=? T1=18+273.15=291.15 T2=38+273.15=311.15 V2=v1t2/t1
10) If I have an unknown quantity of gas held at a temperature of 1195 K in a container with a volume of 25 liters and a pressure of 560 atm, how many moles of gas do I have?
148 comments:
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hi maam!!!
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7) Submarines need to be extremely strong to withstand the extremely high pressure of water pushing down on them. An experimental research submarine with a volume of 15,000 liters has an internal pressure of 1.2 atm. If the pressure of the ocean breaks the submarine forming a bubble with a pressure of 250 atm pushing on it, how big will that bubble be?
P1v1=p2v2
V2=p1v1/p2=v2=(1.2)15000/250
ans.72 L
harlene p. hatalan
hi mam..
7) Submarines need to be extremely strong to withstand the extremely high pressure of water pushing down on them. An experimental research submarine with a volume of 15,000 liters has an internal pressure of 1.2 atm. If the pressure of the ocean breaks the submarine forming a bubble with a pressure of 250 atm pushing on it, how big will that bubble be?
P1v1=p2v2
V2=p1v1/p2=v2=(1.2)15000/250
ans.72 L
harlene p. hatalan
Hazel Paclar
Boyles law
8.) V1= 0.05L
V2= ?
P1= 250 atm
P2= 50.0 atm
V2= V1P1
------
P2
V2= (0.05L)(250atm)
---------------
50.0 atm
V2= 12.5
----
50.0
V2= 0.25L yes
stephanie g.sullano
boyles law
8.)v1=0.05L
V2=?
P1=250 atm
p2=50.0 atm
v2=v1p1
-------
p2
v2=(0.05L) (250 atm)
-----------------
v2=12.5
----
50.0
v2=0.25 L,YES
Priscilla S. Akut
Boyles law
8.) Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver?
V1=0.05L
V2=?
P1=250 atm
P2=50.0 atm
V2=V1P1
----
P2
V2=(0.05L)(250 atm)
----------------
50.0 atm
V2= 12.5
----
50.0
V2= 0.25L yes
2) A man heats a balloon in the oven. If the balloon initially has a volume of 0.4 liters and a temperature of 20 0C, what will the volume of the balloon be after he heats it to a temperature of 250 0C?
V2=v1t2/t1=v2=(0.4)523.15/293.15
Ans.0.71 L
Harlene p. hatalan
8) Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver?
P1v1=p2v2
V2=p1v1/p2=v2=(0.05)250/50.0=v=0.25L,yes
Racma Mauna 3-john
Priscilla S.Akut
Charles law
3.)On hot days, you may have noticed that potato chip bags seem to “inflate”, even though they have not been opened. If I have a 250 mL bag at a temperature of 19 0C, and I leave it in my car which has a temperature of 600 C, what will the new volume of the bag be?
V1=250 mL
V2=?
T1=19+273.15=292.15
T2=60+273.15=333.15
V2=V1T2
----
T1
V2=333.15/292.15(250 mL)
V2=(1.14)(250 mL)
V2=285 mL
Hazel Paclar
3rd yr John
“ Combined Gas Law “
Problem # 1.
P1 = 12 atm
V1 = 23 L
T1 = 200 K
P2 = 14 atm
T2 = 300 K
V2 = ?
V2 = P1V1T2
P2T1
V2 = 12 atm 300 K ( 23 L )
14 atm 200 K
V2 = ( 0.86) ( 1.5 ) ( 23 L )
V2 = ( 1.29) ( 23 L )
V2 = 29.67 / 29.6
Hazel Paclar
3rd Year – John
CHARLE’S LAW
PROBLEM NO. 2
v1 = 0.4 L
T1 = 20 degrees C + 273.15 = 293.15 K
V2 = ?
T2 = 250 degrees C + 273.15 = 523.15 K
V2 = V1T2
T1
V2 = 523.15 K
293.15 K 0.4 L
V2 = 1.7845
V2 = 0.71 L
stephanie g.sullano
charle's law
PROBLEM NO. 2
v1 = 0.4 L
T1 = 20 degrees C + 273.15 = 293.15 K
V2 = ?
T2 = 250 degrees C + 273.15 = 523.15 K
V2 = V1T2
T1
V2 = 523.15 K
293.15 K 0.4 L
V2 = 1.7845
V2 = 0.71 L
stephanie g.sullano
charle's law
PROBLEM NO. 2
v1 = 0.4 L
T1 = 20 degrees C + 273.15 = 293.15 K
V2 = ?
T2 = 250 degrees C + 273.15 = 523.15 K
V2 = V1T2
T1
V2 = 523.15 K
293.15 K 0.4 L
V2 = 1.7845
V2 = 0.71 L
mark jeffrey magparoc
3-john
4) The highest pressure ever produced in a laboratory setting was about 2.0 x 106 atm. If we have a 1.0 x 10-5 liter sample of a gas at that pressure, then release the pressure until it is equal to 0.275 atm, what would the new volume of that gas be? 72.7 L
p1=2000000atm
v1=0.000010 L
p2=0.275 atm
v2=??
p1v1=-p2v2
2000000(0.000010)=0.275(v2)
p1v1/p2=v2
2000000(0.000010)/0.275=v2
20/0.275=v2
v2=72.72727
ANS:
v2=72.7 L
stephanie g. sullano
combined gas law
1.)p1=12 atm
p2=14 atm
v1=23 L
v2=?
T1=200k
T2=300k
p1v1t2
--------
p2t1
v2=(12 atm/14 atm) (300K/200K)(23L)
V2=(0.86) (1.5) (23l)
v2=(1.29)(23 L)
V2=29.67/29.6
Priscilla S.Akut
Combined gas law
1.)If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?
P1=12atm
P2=14atm
V1=23L
V2=?
T1=200K
T2=300K
P1V1T2
V2=------
P2T1
V2=(12atm/14atm)(300K/200k)(23L)
V2=(0.86)(1.5)(23L)
V2=(1.29)(23L)
V2=29.6L
2) A gas takes up a volume of 17 liters, has a pressure of 2.3 atm, and a temperature of 299 K. If I raise the temperature to 350 K and lower the pressure to 1.5 atm, what is the new volume of the gas?
P1v1/t1=p2v2/t2
V2=p1v1t2/t1p2
=(2.3)(17 L)(350 K)/(1.5)(299 K)
Ans.30.5
Harlene P. hatalan
Hazel Paclar
1.)Combined gas law
1.)If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?
P1=12atm
P2=14atm
V1=23L
V2=?
T1=200K
T2=300K
P1V1T2
V2=------
P2T1
V2=(12atm/14atm)(300K/200k)(23L)
V2=(0.86)(1.5)(23L)
V2=(1.29)(23L)
V2=29.6L
Flower Mae S. Nugas
boyles law
v1=0.05,,v2=?,,p1=250atm,,p2=50.0atm
v2=v1p1/p2
v2=(0.05)(250atm)
50.0atm
v2=12.5
50.0
v2=0.25L,,,yes..
florisa yancha
boyle"s law
1.} P1=1.00 atm
473 mL
T1=473+1.00=474
=474 mL
Flower Mae S. Nugas
combined gas law
p1=12atm,,v1=23L,,T1200k,,P2=14atm,,T2=300k,,V2?,,
V2=P1V1T2/P2T1
V2=(12atm/14atm)(300k/200k)(23L
V2=(0.86)(1.5)(23L)
V2=(1.29)(23L)
V2=29.67/29.6
florisa yancha
charle"s law
1) The temperature inside my refrigerator is about 40 Celsius. If I place a balloon in my fridge that initially has a temperature of 220 C and a volume of 0.5 liters, what will be the volume of the balloon when it is fully cooled by my refrigerator?
P1=o.5 atm
P2=? atm
4degree Celsius+22 degree Celsius=26
=26
Combined Gas Law Problems
mark jeffrey magparoc
3-john
1) If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas? 29.6 L
P1=12 atm
P2=14 atm
V1=23 L
V2=????
T1=200 K
T2=300K
P1v1/t1=p2v2/t2
12 atm(23L)/23L=14 atm(?)/300 K
V2=p1v1t2/t1p2
V2=12 atm(23L)(300K)/200 K(14 atm.)
V2=82800/2800=29.57143
Ans;
29.6 L
florisa yancha
dalton"s law
A metal tank contains three gases: oxygen, helium, and nitrogen. If the partial pressures of the three gases in the tank are 35 atm of O2, 5 atm of N2, and 25 atm of He, what is the total pressure inside of the tank?
65 atm
P1=35 atm,5 atm
P2=25 atm
=65 atm
Flower Mae S. Nugas
charles law no. 2
V1=0.4L,,T1=20 degrees C+273.15=293.15K,,V2=?,,T2=250 degreesC+273.15=523.15K,,V2=V1T1
T1
V2=523.15K
293.15K 0.4L
V2=1.7845
V2=0.71L
Charles law
3.)On hot days, you may have noticed that potato chip bags seem to “inflate”, even though they have not been opened. If I have a 250 mL bag at a temperature of 19 0C, and I leave it in my car which has a temperature of 600 C, what will the new volume of the bag be?
V1=250 mL
V2=?
T1=19+273.15=292.15
T2=60+273.15=333.15
V2=V1T2
----
T1
V2=333.15/292.15(250 mL)
V2=(1.14)(250 mL)
V2=285 mL
KARL JULIUS S. DELA CRUZ
III-JOHN
florisa yancha
3-john
the ideal and combined gas laws
3) My car has an internal volume of 2600 liters. If the sun heats my car from a temperature of 200 C to a temperature of 550 C, what will the pressure inside my car be? Assume the pressure was initially 760 mm Hg.
P1=2600 L
P2=?
T1=20 degree Celsius+55
=75
V1=2600 L v2=2600L
Charles’ Law Worksheet
mark jeffrey magparoc
3-john
1) The temperature inside my refrigerator is about 40 Celsius. If I place a balloon in my fridge that initially has a temperature of 220 C and a volume of 0.5 liters, what will be the volume of the balloon when it is fully cooled by my refrigerator? 0.47 L
V1=0.5 L
T2=22’c + 273.15 k=295.15
V2=??
T1=4’c + 273.15k=277.15
V1t1=v2t2
0.5L(277.15)=?(295.15)
V2=0.5(277.15)/295.15
v2=138.5765/295.15
V2=0.469512
Ans:
V2=0.47 L
4) The highest pressure ever produced in a laboratory setting was about 2.0 x 106 atm. If we have a 1.0 x 10-5 liter sample of a gas at that pressure, then release the pressure until it is equal to 0.275 atm, what would the new volume of that gas be? 72.7 L
p1=2000000atm
v1=0.000010 L
p2=0.275 atm
v2=??
p1v1=-p2v2
2000000(0.000010)=0.275(v2)
p1v1/p2=v2
2000000(0.000010)/0.275=v2
20/0.275=v2
v2=72.72727
ANS:
v2=72.7 L
kheyjaymark B.Longaquit
5) Some students believe that teachers are full of hot air. If I inhale 2.2 liters of gas at a temperature of 180 C and it heats to a temperature of 380 C in my lungs, what is the new volume of the gas?
CHARLES LAW
Racma G. Mauna 3 JOHN
V1=2.2L
V2=?
T1=18+273.15=291.15
T2=38+273.15=311.15
V2=v1t2/t1
V2=311.15/291.15(2.2L)
V2=(1.06)(2.2L)
V2=2.35L
Boyles law
8.) V1= 0.05L
V2= ?
P1= 250 atm
P2= 50.0 atm
V2= V1P1
------
P2
V2= (0.05L)(250atm)
---------------
50.0 atm
V2= 12.5
----
50.0
V2= 0.25L yes
Charles law
3.)On hot days, you may have noticed that potato chip bags seem to “inflate”, even though they have not been opened. If I have a 250 mL bag at a temperature of 19 0C, and I leave it in my car which has a temperature of 600 C, what will the new volume of the bag be?
V1=250 mL
V2=?
T1=19+273.15=292.15
T2=60+273.15=333.15
V2=V1T2
----
T1
V2=333.15/292.15(250 mL)
V2=(1.14)(250 mL)
V2=285 mL
joshua delvin ryan garces
boyles law
V1=0.05L
V2=?
P1=250 atm
P2=50.0 atm
V2=V1p1
------
P2
V2=(0.05L)(250atm)
------------
50.0 atm
V2=12.5
-------
50.0
V2+0.25L yes
Mary Ann Hinampas
III-JUDE
aubrey alba
Boyles law
8.) Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver?
V1=0.05L
V2=?
P1=250 atm
P2=50.0 atm
V2=V1P1
----
P2
V2=(0.05L)(250 atm)
----------------
50.0 atm
V2= 12.5
----
50.0
V2= 0.25L yes
boyles law
ana marie g. hinampas
V1=0.05L
V2=?
P1=250 atm
P2=50.0 atm
V2=V1p1
------
P2
V2=(0.05L)(250atm)
------------
50.0 atm
V2=12.5
-------
50.0
V2+0.25L yes
1.)Combined gas law
1.)If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?
P1=12atm
P2=14atm
V1=23L
V2=?
T1=200K
T2=300K
P1V1T2
V2=------
P2T1
V2=(12atm/14atm)(300K/200k)(23L)
V2=(0.86)(1.5)(23L)
V2=(1.29)(23L)
V2=29.6L
ana marie g.hinampas
A(n) __________________ is used to lower the energy required to make a reaction take place. It makes chemical reactions go faster without being consumed.
ANSWER: catalyst
ANSWERED BY: alma mae mahasol
The thing we measure when we want to determine the average kinetic energy of random motion in the particles of a substance is _temperature_________________.
ANSWER:temperature
ANSWERED BY:alma mae mahasol
The __________________ is used to describe how much energy is produced or used during a chemical change.
ANSWER:heat of reaction (or enthalpy of reaction)
ANSWERED BY: alma mae mahasol
1) If I have 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature?
ANSWER: 205 K
ANSWERED BY: alma mae mahasol
2) If I have an unknown quantity of gas at a pressure of 1.2 atm, a volume of 31 liters, and a temperature of 87 0C, how many moles of gas do I have?
ANSWER: 1.26 moles
ANSWERED BY: alma mae mahasol
3) If I contain 3 moles of gas in a container with a volume of 60 liters and at a temperature of 400 K, what is the pressure inside the container?
ANSWER:1.64 atm
ANSWERED BY: alma narido
4) If I have 7.7 moles of gas at a pressure of 0.09 atm and at a temperature of 56 0C, what is the volume of the container that the gas is in?
ANSWER:2310 L
ANSWERED BY: alma narido
5) If I have 17 moles of gas at a temperature of 67 0C, and a volume of 88.89 liters, what is the pressure of the gas?
ANSWER:5.34 atm
ANSWERED BY: alma narido
6) If I have an unknown quantity of gas at a pressure of 0.5 atm, a volume of 25 liters, and a temperature of 300 K, how many moles of gas do I have?
ANSWER:0.51 moles
ANSWERED BY: alma narido
7) If I have 21 moles of gas held at a pressure of 78 atm and a temperature of 900 K, what is the volume of the gas?
ANSWER: 19.9 L
ANSWERED BY: alma narido
9) If I have 2.4 moles of gas held at a temperature of 97 0C and in a container with a volume of 45 liters, what is the pressure of the gas?
ANSWER:1.62 atm
ANSWERED BY: raiza kris francisco
10) If I have an unknown quantity of gas held at a temperature of 1195 K in a container with a volume of 25 liters and a pressure of 560 atm, how many moles of gas do I have?
ANSWER:143 moles
ANSWERED BY: raiza kris francisco
11) If I have 0.275 moles of gas at a temperature of 75 K and a pressure of 1.75 atmospheres, what is the volume of the gas?
ANSWER:0.97 L
ANSWERED BY: raiza kris francisco
Another word for freezing is __________________.
ANSWER: fusion
ANSWERED BY: raiza kris francisco
__________________ reactions require energy in order to take place.
ANSWER: endothermic
ANSWERED BY: raiza kris francisco
The thing we measure when we want to determine the average kinetic energy of random motion in the particles of a substance is_________________. *answer:temperature
The thing we measure when we want to determine the average kinetic energy of random motion in the particles of a substance is_________________.
*answer:temperature
1.00 L of a gas at standard temperature and pressure is compressed to 473 mL. What is the new pressure of the gas? *answer;2.11 atm
Part of the reason that conventional explosives cause so much damage is that their detonation produces a strong shock wave that can knock things down. While using explosives to knock down a building, the shock wave can be so strong that 12 liters of gas will reach a pressure of 3.8 x 104 mm Hg. When the shock wave passes and the gas returns to a pressure of 760 mm Hg, what will the volume of that gas be? *answer:600L
he temperature inside my refrigerator is about 40 Celsius. If I place a balloon in my fridge that initially has a temperature of 220 C and a volume of 0.5 liters, what will be the volume of the balloon when it is fully cooled by my refrigerator? *answer:0.47L
A man heats a balloon in the oven. If the balloon initially has a volume of 0.4 liters and a temperature of 20 0C, what will the volume of the balloon be after he heats it to a temperature of 250 0C? *answer:0.71L
submitted by CHERIE MAE GALARPE
Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver? answer:v=0.25L,yes submitted by CHERIE MAE GALARPE
Boyles’ Law
1) 1.00 L of a gas at standard temperature and pressure is compressed to 473 mL. What is the new pressure of the gas?
Given:
V1 =1.00L P1=1atm V2=473mL P2=?
Volume is inversely proportion to pressure. A decrease in volume means an increase in pressure. Hence, we multiply P1 by a factor of volume that will increase its value. FORMULA: P1V1=P1V2
SOLUTION:
P2=(1atm)(1000ml)
473mL
P2=2.11atm
Kimjay B.Dulalas
Charles’ Law Worksheet
1) The temperature inside my refrigerator is about 40 Celsius. If I place a balloon in my fridge that initially has a temperature of 220 C and a volume of 0.5 liters, what will be the volume of the balloon when it is fully cooled by my refrigerator?
Given:
V1= 0.5L T1 =40 C + 273 K
V2= ? T2= 220 C + 273 K
Formula:
V1 = V2
T1 T2
Solution:
V2= V1T2
T1
V2= (0.5)(277 K)
295 K
V2 = 0.47 L
)
Combined Gas Law Problems
Use the combined gas law to solve the following problems:
1) If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?
Given:
V1 = 23 L P1 = 12 atm T1 = 200 K
V2 = ? P2 = 14 atm T2 = 300 K
Formula:
P1V1 = P2V2
T1 T2
Solution:
V2 = P1V1T2
T1P2
V2= (12 atm)(23 L)(300 K)
(200 K)(14 atm)
V2 = 29.6 L
m mercy tuhod boyleslaw 8} V1=0.05L V2? ...P1=250atm P2=50.0atm V2=V1P1 ...V2={0.05L}{250atm} ...50atm V2=12.5 ...50.0 v2=0.25L ...ANS.YES!
mercy tuhod combined gas laws#1 T1=? P1=5.4atm V1=120L T1=P1V1 T1=5.4atmX120L T1=648.
mercy tuhod charles law#1 T1=4CELCIUS T2=22 V1=0.5L V2=? V2=V1XT2/T1 V2=0.5X22/4 V2=2.75
mercytuhod gaslaws#1 P1=5.6atm V1=12L T1? T1=P1V1 T1=5.6atm X12L T1=67.2
gezelle marie japona charle's law 2) A man heats a balloon in the oven. If the balloon initially has a volume of 0.4 liters and a temperature of 20 0C, what will the volume of the balloon be after he heats it to a temperature of 250 0C?
PROBLEM NO. 2
v1 = 0.4 L
T1 = 20 degrees C + 273.15 = 293.15 K
V2 = ?
T2 = 250 degrees C + 273.15 = 523.15 K
V2 = V1T2
T1
V2 = 523.15 K
293.15 K 0.4 L
V2 = 1.7845
V2 = 0.71
gezelle marie japona combined gas law problem 1) If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?
Problem # 1.
P1 = 12 atm
V1 = 23 L
T1 = 200 K
P2 = 14 atm
T2 = 300 K
V2 = ?
V2 = P1V1T2
P2T1
V2 = 12 atm 300 K ( 23 L )
14 atm 200 K
V2 = ( 0.86) ( 1.5 ) ( 23 L )
V2 = ( 1.29) ( 23 L )
V2 = 29.67 / 29.6
gezelle marie japona dalton's law A metal tank contains three gases: oxygen, helium, and nitrogen. If the partial pressures of the three gases in the tank are 35 atm of O2, 5 atm of N2, and 25 atm of He, what is the total pressure inside of the tank?
65 atm
P1=35 atm,5 atm
P2=25 atm
=65 atm
gezelle marie8.) Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver?
V1=0.05L
V2=?
P1=250 atm
P2=50.0 atm
V2=V1P1
----
P2
V2=(0.05L)(250 atm)
----------------
50.0 atm
V2= 12.5
----
50.0
V2= 0.25L japona
Carlo Montano M. Radaza
3-John
V1=0.05L
V2=?
P1=250 atm
P2=50.0 atm
V2=P1V1/V2
--------------
V2=(250)(0.05)/50.0
--------------
V2=12.5/50.0
V2=0.25L,YES
Ma.Jenifer G. Tibay Boyles Low 8.V1=0.05L V2=? P1=250atm P2=50.0atm v2=v1p1 _______ p1 V2=(0.05L)(250atm) _________________ 50.0atm V2=12.5 _______ 50.0 V2=0.25L , YES
V1=0.05
V2=?
P1=250 atom
P2=50.0 atom
V2=P1V1/P2
V2=(250)(0.05)/50.0L
V2=12.5/50.0L
V2=0.25L,YES
V1=0.05L
V2=?
P1=250
P2=50.0
V2=V1P1/V2
V2=(0.05)(250)/50.0
V2=12.5/50.0
V2=0.25L,YES
charles law
1) The temperature inside my refrigeratoris about 4 degrees Celcius.if i place a ballonin my fridge initially has a temp. of 22 degrees celcius and a volume of 0.5 liters.what will be the volume of the balloon when its fully cooled in my refrigerator?
answer:
FORMULA:
V1/v2=t1/t2
v1= 0.5
V2=?
t1=4 degrees celcius
t2=22 degrees celcius
t1=4+273k= 277k
t2=22+273k=295k
(277k)(0.5)/ 295k
answer:0.46949153
round of to 0.47
Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver?
answer:
8.) V1= 0.05L
V2= ?
P1= 250 atm
P2= 50.0 atm
V2= V1P1
------
P2
V2= (0.05L)(250atm)
---------------
50.0 atm
V2= 12.5
----
50.0
V2= 0.25L yes
ruelyn yecyec
Boyles law
8.) V1= 0.05L
V2= ?
P1= 250 atm
P2= 50.0 atm
V2= V1P1
------
P2
V2= (0.05L)(250atm)
---------------
50.0 atm
V2= 12.5
----
50.0
V2= 0.25L yes
ruelyn yecyec
problem no.2
1) If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?
Given:
V1 = 23 L P1 = 12 atm T1 = 200 K
V2 = ? P2 = 14 atm T2 = 300 K
Formula:
P1V1 = P2V2
T1 T2
Solution:
V2 = P1V1T2
T1P2
V2= (12 atm)(23 L)(300 K)
(200 K)(14 atm)
V2 = 29.6 L
ruelyn yecyec
Boyles’ Law
1) 1.00 L of a gas at standard temperature and pressure is compressed to 473 mL. What is the new pressure of the gas?
Given:
V1 =1.00L P1=1atm V2=473mL P2=?
Volume is inversely proportion to pressure. A decrease in volume means an increase in pressure. Hence, we multiply P1 by a factor of volume that will increase its value. FORMULA: P1V1=P1V2
SOLUTION:
P2=(1atm)(1000ml)
473mL
P2=2.11atm
rosemarie kiamco
Boyles law
8.) V1= 0.05L
V2= ?
P1= 250 atm
P2= 50.0 atm
V2= V1P1
------
P2
V2= (0.05L)(250atm)
---------------
50.0 atm
V2= 12.5
----
50.0
V2= 0.25L yes
rosemarie kiamco
Charles law
3.)On hot days, you may have noticed that potato chip bags seem to “inflate”, even though they have not been opened. If I have a 250 mL bag at a temperature of 19 0C, and I leave it in my car which has a temperature of 600 C, what will the new volume of the bag be?
V1=250 mL
V2=?
T1=19+273.15=292.15
T2=60+273.15=333.15
V2=V1T2
----
T1
V2=333.15/292.15(250 mL)
V2=(1.14)(250 mL)
V2=285 mL
rosemarie kiamco
4) The highest pressure ever produced in a laboratory setting was about 2.0 x 106 atm. If we have a 1.0 x 10-5 liter sample of a gas at that pressure, then release the pressure until it is equal to 0.275 atm, what would the new volume of that gas be? 72.7 L
p1=2000000atm
v1=0.000010 L
p2=0.275 atm
v2=??
p1v1=-p2v2
2000000(0.000010)=0.275(v2)
p1v1/p2=v2
2000000(0.000010)/0.275=v2
20/0.275=v2
v2=72.72727
ANS:
v2=72.7 L
rachelle bahancharle's law 2) A man heats a balloon in the oven. If the balloon initially has a volume of 0.4 liters and a temperature of 20 0C, what will the volume of the balloon be after he heats it to a temperature of 250 0C?
PROBLEM NO. 2
v1 = 0.4 L
T1 = 20 degrees C + 273.15 = 293.15 K
V2 = ?
T2 = 250 degrees C + 273.15 = 523.15 K
V2 = V1T2
T1
V2 = 523.15 K
293.15 K 0.4 L
V2 = 1.7845
V2 = 0.71
8.) Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver?
V1=0.05L
V2=?
P1=250 atm
P2=50.0 atm
V2=V1P1
----
P2
V2=(0.05L)(250 atm)
----------------
50.0 atm
V2= 12.5
----
50.0
V2= 0.25L
dalton's law A metal tank contains three gases: oxygen, helium, and nitrogen. If the partial pressures of the three gases in the tank are 35 atm of O2, 5 atm of N2, and 25 atm of He, what is the total pressure inside of the tank?
65 atm
P1=35 atm,5 atm
P2=25 atm
=65 atm
combined gas law problem 1) If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?
Problem # 1.
P1 = 12 atm
V1 = 23 L
T1 = 200 K
P2 = 14 atm
T2 = 300 K
V2 = ?
V2 = P1V1T2
P2T1
V2 = 12 atm 300 K ( 23 L )
14 atm 200 K
V2 = ( 0.86) ( 1.5 ) ( 23 L )
V2 = ( 1.29) ( 23 L )
V2 = 29.67 / 29.6
Erlin Mae Chan Boyles Law 8.)V1=0.05L V2=? P1=250atm P2=50.0atm V2=V1P1 ----P2 V2=(0.05L)(250atm) ----------- 50.0atm V=12.5 ----- 50.0 V2=0.25L,yes
Erlin Mae Chan Combined Gas Law 1.)P1=12atm V1=23L T1=200K P2=14atm T2=300K V2=? V2=P1V1P2 ----- P2T1 V2=12atm 300k(23L) ------ 14atm 200k V2=(0.86)(1.5)(23L) V2=(1.29)(23L) V2=29.6
jonalyn hernaiz
Boyles law
8.) Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver?
V1=0.05L
V2=?
P1=250 atm
P2=50.0 atm
V2=V1P1
----
P2
V2=(0.05L)(250 atm)
----------------
50.0 atm
V2= 12.5
----
50.0
V2= 0.25L yes
March 11,2008 1:30PM III-JUDE
maurice sagbigsal
boyles law
V1=0.05L
V2=?
P1=250 atm
P2=50.0 atm
V2=V1p1
------
P2
V2=(0.05L)(250atm)
------------
50.0 atm
V2=12.5
-------
50.0
V2+0.25L yes
III-JUDE maurice sagbigsal
maricho macas
Combined gas law
1.)If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?
P1=12atm
P2=14atm
V1=23L
V2=?
T1=200K
T2=300K
P1V1T2
V2=------
P2T1
V2=(12atm/14atm)(300K/200k)(23L)
V2=(0.86)(1.5)(23L)
V2=(1.29)(23L)
V2=29.6L
III-JUDE maricho macas
charity raluto
boyles law
v1=0.05,,v2=?,,p1=250atm,,p2=50.0atm
v2=v1p1/p2
v2=(0.05)(250atm)
50.0atm
v2=12.5
50.0
v2=0.25L,,,yes..
III-JUDE charity raluto
rosemarie dacuyan
III-jude
boyles law
8.) Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver?
V1=0.05L
V2=?
P1=250 atm
P2=50.0 atm
V2=V1P1
----
P2
V2=(0.05L)(250 atm)
----------------
50.0 atm
V2= 12.5
----
50.0
V2= 0.25L yes
March 12,2008
rosemarie dacuyan
jesivel jadap combined gas law problem 1) If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?
Problem # 1.
P1 = 12 atm
V1 = 23 L
T1 = 200 K
P2 = 14 atm
T2 = 300 K
V2 = ?
V2 = P1V1T2
P2T1
V2 = 12 atm 300 K ( 23 L )
14 atm 200 K
V2 = ( 0.86) ( 1.5 ) ( 23 L )
V2 = ( 1.29) ( 23 L )
V2 = 29.67 / 29.6
march 12 200
jesivel jadap
III-JUDE
jesivel jadap
III-JUDE
3.)On hot days, you may have noticed that potato chip bags seem to “inflate”, even though they have not been opened. If I have a 250 mL bag at a temperature of 19 0C, and I leave it in my car which has a temperature of 600 C, what will the new volume of the bag be?
V1=250 mL
V2=?
T1=19+273.15=292.15
T2=60+273.15=333.15
V2=V1T2
----
T1
V2=333.15/292.15(250 mL)
V2=(1.14)(250 mL)
V2=285 mL
JESIVEL JADAP
III-JUDE
Combined gas law
1.)If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?
P1=12atm
P2=14atm
V1=23L
V2=?
T1=200K
T2=300K
P1V1T2
V2=------
P2T1
V2=(12atm/14atm)(300K/200k)(23L)
V2=(0.86)(1.5)(23L)
V2=(1.29)(23L)
V2=29.6L
January 10, 2008 3:58 PM
noemi fabria said...
boyles law
V1=0.05L
V2=?
P1=250 atm
P2=50.0 atm
V2=V1p1
------
P2
V2=(0.05L)(250atm)
------------
50.0 atm
V2=12.5
-------
50.0
V2+0.25L yes
lorraine g.calam
III-JUDE
7) Submarines need to be extremely strong to withstand the extremely high pressure of water pushing down on them. An experimental research submarine with a volume of 15,000 liters has an internal pressure of 1.2 atm. If the pressure of the ocean breaks the submarine forming a bubble with a pressure of 250 atm pushing on it, how big will that bubble be?
P1v1=p2v2
V2=p1v1/p2=v2=(1.2)15000/250
ans.72 L
LORRAINE G.CALAM
MARCH 12,2008
ma.) Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver?
V1=0.05L
V2=?
P1=250 atm
P2=50.0 atm
V2=V1P1
----
P2
V2=(0.05L)(250 atm)
----------------
50.0 atm
V2= 12.5
----
50.0
V2= 0.25l yes marianne borjal 11
KaRen sAiD...
boyles law
v1=0.05,,v2=?,,p1=250atm,,p2=50.0atm
v2=v1p1/p2
v2=(0.05)(250atm)
50.0atm
v2=12.5
50.0
v2=0.25L,,,yes..
angel rose marie ybanez combined gas law problem 1) If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?
Problem # 1.
P1 = 12 atm
V1 = 23 L
T1 = 200 K
P2 = 14 atm
T2 = 300 K
V2 = ?
V2 = P1V1T2
P2T1
V2 = 12 atm 300 K ( 23 L )
14 atm 200 K
V2 = ( 0.86) ( 1.5 ) ( 23 L )
V2 = ( 1.29) ( 23 L )
V2 = 29.67 / 29.6
march 12 200
angel rose marie ybanez
III-JUDE
March 11, 2008 9:28 PM
combined gas law
Conson,Kevin Jon C.
III-Jude
p1=12atm,,v1=23L,,T1200k,,P2=14atm,,T2=300k,,V2?,,
V2=P1V1T2/P2T1
V2=(12atm/14atm)(300k/200k)(23L
V2=(0.86)(1.5)(23L)
V2=(1.29)(23L)
V2=29.67/29.6
Boyles law
8.) Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver?
V1=0.05L
V2=?
P1=250 atm
P2=50.0 atm
V2=V1P1
----
P2
V2=(0.05L)(250 atm)
----------------
50.0 atm
V2= 12.5
----
50.0
V2= 0.25L yes
rapog sheila
III-JUDE
Boyles law
8.) Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver?
V1=0.05L
V2=?
P1=250 atm
P2=50.0 atm
V2=V1P1
----
P2
V2=(0.05L)(250 atm)
----------------
50.0 atm
V2= 12.5
----
50.0
V2= 0.25L yes
MARCH 12,2OO8
8) Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver?
P1v1=p2v2
V2=p1v1/p2=v2=(0.05)250/50.0=v=0.25L,yes KaReN GANINAY III-JUDE....
boyles law
angel rose marie ybanez
V1=0.05L
V2=?
P1=250 atm
P2=50.0 atm
V2=V1p1
------
P2
V2=(0.05L)(250atm)
------------
50.0 atm
V2=12.5
-------
50.0
V2+0.25L yes
March 11, 2008 9:33 PM
Combined gas law
1.)If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?
P1=12atm
P2=14atm
V1=23L
V2=?
T1=200K
T2=300K
P1V1T2
V2=------
P2T1
V2=(12atm/14atm)(300K/200k)(23L)
V2=(0.86)(1.5)(23L)
V2=(1.29)(23L)
V2=29.6L
ana marie g.hinampas
January 11, 2008 3:20 AM
Comment deleted
klyndon Boyles law
8.) Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver?
V1=0.05L
V2=?
P1=250 atm
P2=50.0 atm
V2=V1P1
----
P2
V2=(0.05L)(250 atm)
----------------
50.0 atm
V2= 12.5
----
50.0
V2= 0.25L yes
genson III-JUDE
Charles law
3.)On hot days, you may have noticed that potato chip bags seem to “inflate”, even though they have not been opened. If I have a 250 mL bag at a temperature of 19 0C, and I leave it in my car which has a temperature of 600 C, what will the new volume of the bag be?
V1=250 mL
V2=?
T1=19+273.15=292.15
T2=60+273.15=333.15
V2=V1T2
----
T1
V2=333.15/292.15(250 mL)
V2=(1.14)(250 mL)
V2=285 mL
kevin jon conson
III-jude
Combined gas law
1.)If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?
P1=12atm
P2=14atm
V1=23L
V2=?
T1=200K
T2=300K
P1V1T2
V2=------
P2T1
V2=(12atm/14atm)(300K/200k)(23L)
V2=(0.86)(1.5)(23L)
V2=(1.29)(23L)
V2=29.6L
ana marie g.hinampas
January 11, 2008 3:20 AM
Comment deleted
analeth cartajena
III-JUDE.)On hot days, you may have noticed that potato chip bags seem to “inflate”, even though they have not been opened. If I have a 250 mL bag at a temperature of 19 0C, and I leave it in my car which has a temperature of 600 C, what will the new volume of the bag be?
V1=250 mL
V2=?
T1=19+273.15=292.15
T2=60+273.15=333.15
V2=V1T2
----
T1
V2=333.15/292.15(250 mL)
V2=(1.14)(250 mL)
V2=285 mL
analeth cartajena
III-JUDE
jesivel jadap IBoyles law
8.) Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver?
V1=0.05L
V2=?
P1=250 atm
P2=50.0 atm
V2=V1P1
----
P2
V2=(0.05L)(250 atm)
----------------
50.0 atm
V2= 12.5
----
50.0
V2= 0.25L yes
II-JUDE
klyndon genson
III-JUDE
7) Submarines need to be extremely strong to withstand the extremely high pressure of water pushing down on them. An experimental research submarine with a volume of 15,000 liters has an internal pressure of 1.2 atm. If the pressure of the ocean breaks the submarine forming a bubble with a pressure of 250 atm pushing on it, how big will that bubble be?
P1v1=p2v2
V2=p1v1/p2=v2=(1.2)15000/250
ans.72 L
harlene p. hatalan
vernedette dagaya
III-JUDE
Charles’ Law Worksheet
1) The temperature inside my refrigerator is about 40 Celsius. If I place a balloon in my fridge that initially has a temperature of 220 C and a volume of 0.5 liters, what will be the volume of the balloon when it is fully cooled by my refrigerator?
Given:
V1= 0.5L T1 =40 C + 273 K
V2= ? T2= 220 C + 273 K
Formula:
V1 = V2
T1 T2
Solution:
V2= V1T2
T1
V2= (0.5)(277 K)
295 K
V2 = 0.47 L
E
III-JUDE
vernedette dagaya
III-JUDE
Charles’ Law Worksheet
1) The temperature inside my refrigerator is about 40 Celsius. If I place a balloon in my fridge that initially has a temperature of 220 C and a volume of 0.5 liters, what will be the volume of the balloon when it is fully cooled by my refrigerator?
Given:
V1= 0.5L T1 =40 C + 273 K
V2= ? T2= 220 C + 273 K
Formula:
V1 = V2
T1 T2
Solution:
V2= V1T2
T1
V2= (0.5)(277 K)
295 K
V2 = 0.47 L
E
III-JUDE
jonalyn hernaiz
III-JUDEcharle's law
PROBLEM NO. 2
v1 = 0.4 L
T1 = 20 degrees C + 273.15 = 293.15 K
V2 = ?
T2 = 250 degrees C + 273.15 = 523.15 K
V2 = V1T2
T1
V2 = 523.15 K
293.15 K 0.4 L
V2 = 1.7845
V2 = 0.71 L
III-JUDE
JOnalyn CONcepcion Romea Hernaiz
AnGel RoSe YBANez
III-jUdE..
2) A man heats a balloon in the oven. If the balloon initially has a volume of 0.4 liters and a temperature of 20 0C, what will the volume of the balloon be after he heats it to a temperature of 250 0C?
V2=v1t2/t1=v2=(0.4)523.15/293.15
Ans.0.71 L
lord neil C. actub
lll-jude
Charles law
3.)On hot days, you may have noticed that potato chip bags seem to “inflate”, even though they have not been opened. If I have a 250 mL bag at a temperature of 19 0C, and I leave it in my car which has a temperature of 600 C, what will the new volume of the bag be?
V1=250 mL
V2=?
T1=19+273.15=292.15
T2=60+273.15=333.15
V2=V1T2
----
T1
V2=333.15/292.15(250 mL)
V2=(1.14)(250 mL)
V2=285 mL
Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver?
answer:
8.) V1= 0.05L
V2= ?
P1= 250 atm
P2= 50.0 atm
V2= V1P1
------
P2
V2= (0.05L)(250atm)
---------------
50.0 atm
V2= 12.5
----
50.0
V2= 0.25L yes
Combined gas law
1.)If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?
P1=12atm
P2=14atm
V1=23L
V2=?
T1=200K
T2=300K
P1V1T2
V2=------
P2T1
V2=(12atm/14atm)(300K/200k)(23L)
V2=(0.86)(1.5)(23L)
V2=(1.29)(23L)
V2=29.6L
1.00 L of a gas at standard temperature and pressure is compressed to 473 mL. What is the new pressure of the gas?
Given:
V1 =1.00L P1=1atm V2=473mL P2=?
Volume is inversely proportion to pressure. A decrease in volume means an increase in pressure. Hence, we multiply P1 by a factor of volume that will increase its value. FORMULA: P1V1=P1V2
SOLUTION:
P2=(1atm)(1000ml)
473mL
P2=2.11atm
Submarines need to be extremely strong to withstand the extremely high pressure of water pushing down on them. An experimental research submarine with a volume of 15,000 liters has an internal pressure of 1.2 atm. If the pressure of the ocean breaks the submarine forming a bubble with a pressure of 250 atm pushing on it, how big will that bubble be?
P1v1=p2v2
V2=p1v1/p2=v2=(1.2)15000/250
ans.72 L
Boyles law
8.) V1= 0.05L
V2= ?
P1= 250 atm
P2= 50.0 atm
V2= V1P1
------
P2
V2= (0.05L)(250atm)
---------------
50.0 atm
V2= 12.5
----
50.0
V2= 0.25L yes
SANDRA MAE CAIREL
III-JUDE
Charles law
3.)On hot days, you may have noticed that potato chip bags seem to “inflate”, even though they have not been opened. If I have a 250 mL bag at a temperature of 19 0C, and I leave it in my car which has a temperature of 600 C, what will the new volume of the bag be?
V1=250 mL
V2=?
T1=19+273.15=292.15
T2=60+273.15=333.15
V2=V1T2
----
T1
V2=333.15/292.15(250 mL)
V2=(1.14)(250 mL)
V2=285 mL
SANDRA MAE CAIREL
MARCH 12,2008
SANDRA MAE CAIREL
III-JUDE
Charles law
3.)On hot days, you may have noticed that potato chip bags seem to “inflate”, even though they have not been opened. If I have a 250 mL bag at a temperature of 19 0C, and I leave it in my car which has a temperature of 600 C, what will the new volume of the bag be?
V1=250 mL
V2=?
T1=19+273.15=292.15
T2=60+273.15=333.15
V2=V1T2
----
T1
V2=333.15/292.15(250 mL)
V2=(1.14)(250 mL)
V2=285 mL
SANDRA MAE CAIREL
MARCH 12,2008
DOLLY GRACE ACERA
III-JUDE
8.) Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver?
V1=0.05L
V2=?
P1=250 atm
P2=50.0 atm
V2=V1P1
----
P2
V2=(0.05L)(250 atm)
----------------
50.0 atm
V2= 12.5
----
50.0
V2= 0.25L
MARCH 12,2008
DOLLY GRACE ACERA
III-JUDE
8.) Divers get “the bends” if they come up too fast because gas in their blood expands, forming bubbles in their blood. If a diver has 0.05 L of gas in his blood under a pressure of 250 atm, then rises instantaneously to a depth where his blood has a pressure of 50.0 atm, what will the volume of gas in his blood be? Do you think this will harm the diver?
V1=0.05L
V2=?
P1=250 atm
P2=50.0 atm
V2=V1P1
----
P2
V2=(0.05L)(250 atm)
----------------
50.0 atm
V2= 12.5
----
50.0
V2= 0.25L
MARCH 12,2008
7) Submarines need to be extremely strong to withstand the extremely high pressure of water pushing down on them. An experimental research submarine with a volume of 15,000 liters has an internal pressure of 1.2 atm. If the pressure of the ocean breaks the submarine forming a bubble with a pressure of 250 atm pushing on it, how big will that bubble be?
P1v1=p2v2
V2=p1v1/p2=v2=(1.2)15000/250
ans.72 L
kevin jon conson
III-jude
Boyles law
8.) V1= 0.05L
V2= ?
P1= 250 atm
P2= 50.0 atm
V2= V1P1
------
P2
V2= (0.05L)(250atm)
---------------
50.0 atm
V2= 12.5
----
50.0
V2= 0.25L yes
Charles law
3.)On hot days, you may have noticed that potato chip bags seem to “inflate”, even though they have not been opened. If I have a 250 mL bag at a temperature of 19 0C, and I leave it in my car which has a temperature of 600 C, what will the new volume of the bag be?
V1=250 mL
V2=?
T1=19+273.15=292.15
T2=60+273.15=333.15
V2=V1T2
----
T1
V2=333.15/292.15(250 mL)
V2=(1.14)(250 mL)
V2=285 mL
kevin jon conson
III-jude
Submarines need to be extremely strong to withstand the extremely high pressure of water pushing down on them. An experimental research submarine with a volume of 15,000 liters has an internal pressure of 1.2 atm. If the pressure of the ocean breaks the submarine forming a bubble with a pressure of 250 atm pushing on it, how big will that bubble be?
P1v1=p2v2
V2=p1v1/p2=v2=(1.2)15000/250
ans.72 L
2) A man heats a balloon in the oven. If the balloon initially has a volume of 0.4 liters and a temperature of 20 0C, what will the volume of the balloon be after he heats it to a temperature of 250 0C?
V2=v1t2/t1=v2=(0.4)523.15/293.15
Ans.0.71 L
march 12,2008
CHARLE’S LAW
PROBLEM NO. 2
v1 = 0.4 L
T1 = 20 degrees C + 273.15 = 293.15 K
V2 = ?
T2 = 250 degrees C + 273.15 = 523.15 K
V2 = V1T2
T1
V2 = 523.15 K
293.15 K 0.4 L
V2 = 1.7845
V2 = 0.71 L
March 12, 2008
4) The highest pressure ever produced in a laboratory setting was about 2.0 x 106 atm. If we have a 1.0 x 10-5 liter sample of a gas at that pressure, then release the pressure until it is equal to 0.275 atm, what would the new volume of that gas be? 72.7 L
p1=2000000atm
v1=0.000010 L
p2=0.275 atm
v2=??
p1v1=-p2v2
2000000(0.000010)=0.275(v2)
p1v1/p2=v2
2000000(0.000010)/0.275=v2
20/0.275=v2
v2=72.72727
ANS:
v2=72.7 L
March 12, 2008
combined gas law
1.)p1=12 atm
p2=14 atm
v1=23 L
v2=?
T1=200k
T2=300k
p1v1t2
--------
p2t1
v2=(12 atm/14 atm) (300K/200K)(23L)
V2=(0.86) (1.5) (23l)
v2=(1.29)(23 L)
V2=29.67/29.6
March 12, 2008
dalton"s law
A metal tank contains three gases: oxygen, helium, and nitrogen. If the partial pressures of the three gases in the tank are 35 atm of O2, 5 atm of N2, and 25 atm of He, what is the total pressure inside of the tank?
65 atm
P1=35 atm,5 atm
P2=25 atm
=65 atm
March 12, 2008
5) Some students believe that teachers are full of hot air. If I inhale 2.2 liters of gas at a temperature of 180 C and it heats to a temperature of 380 C in my lungs, what is the new volume of the gas?
CHARLES LAW
Racma G. Mauna 3 JOHN
V1=2.2L
V2=?
T1=18+273.15=291.15
T2=38+273.15=311.15
V2=v1t2/t1
V2=311.15/291.15(2.2L)
V2=(1.06)(2.2L)
V2=2.35L
March 12, 2008
6) If I have an unknown quantity of gas at a pressure of 0.5 atm, a volume of 25 liters, and a temperature of 300 K, how many moles of gas do I have?
ANSWER:0.51 moles
March 12, 2008
9) If I have 2.4 moles of gas held at a temperature of 97 0C and in a container with a volume of 45 liters, what is the pressure of the gas?
ANSWER:1.62 atm
March 12, 2008
10) If I have an unknown quantity of gas held at a temperature of 1195 K in a container with a volume of 25 liters and a pressure of 560 atm, how many moles of gas do I have?
ANSWER:143 moles
March 12, 2008
11) If I have 0.275 moles of gas at a temperature of 75 K and a pressure of 1.75 atmospheres, what is the volume of the gas?
ANSWER:0.97 L
March 12, 2008
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